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167xss的简单介绍

本文目录一览:

pro e5.0 license request failed for feature PROE_200 -2

1.运行Setup.exe

2.记下PTC主机ID

3.复制破解目录内的"ptc_licfile.dat"到硬盘.并用记事本打开。将里面所有的"00-00-00-00-00-00"改为你的PTC主机ID后保存

4.开始安装软件到指定许可证服务器时选"锁定的许可证文件"后选修改后的"ptc_licfile.dat"

5.安装完成后将破解目录内"ptc.pro engineer.wildfire.4.0.win32-patch.exe"复制到"安装目录下\i486_nt\obj folder"目录内并运行

6.编辑“安装目录下\bin\proev.bat

改为以下的文本

change "%start_cmd% "%CGTECH_JRE%\bin\javaw" -Xms16m -Xmx64m -Xss4m -classpath "%CGTECH_CLASSES%;%CGTECH_CLASSES%\CGTech.jar" Vericut %argstr%" in

"%start_cmd% "%CGTECH_JRE%\bin\javaw" -Xms16m -Xmx64m -Xss4m -classpath "%CGTECH_CLASSES%;%CGTECH_CLASSES%\CGTech.jar" Vericut %argstr% PTC_KEY=0"

(add PTC_KEY=0)

7.运行软件即可

把下面文件复制到记事本 保存为DAT后缀名的文件 一下是proe4.0版本的许可证

###################################################################

#

# replace 00-00-00-00-00-00 in every-feature with your real ptc_hostid

# as shown in setup

#

###################################################################

INCREMENT PROE_DDiTy ptc_d 29.0 permanent uncounted \

VENDOR_STRING="VSVER=2.0 LO=(0,3,6,7,9,10,14,16,17,19,21,22, \

23,24,25,26,29,30,31,32,34,35,36,37,40,41,45,47,48,51,52,53, \

54,55,56,57,59,60,61,62,63,65,66,67,69,71,72,73,74,77,91,92, \

93,94,97,100,104,106,108,115,116,117,118,119,120,121,122,123, \

125,126,127,128, 131,133,134,135, 137,139,140,141,148,155,156, \

158,160,163,164,167,168,187,188,189,190,191,192,193,194,208,209,210, \

213,214,218,219,220,221,222,223,224,251,253,259,260,261,262,263,264,275)" SUPERSEDE \

HOSTID=PTC_HOSTID=00-00-00-00-00-00 vendor_info="VIVER=2.0 EXTERNAL_NAME=" ISSUER=ODT \

ISSUED=2-apr-2006 NOTICE=PTC SN=07071982 SIGN="092F DBD8 F7BA \

EC9D 51E5 453C 93A1 D63D 0BC7 3126 8493 2C23 32A9 A98F 8BC0 1BEB \

0F0F 5C63 6933 5B61 613F 0CFB 235B 9C1B B39E 274F 2E5A 60E1 1FEF \

DE6A" SIGN2="092F DBD8 F7BA EC9D 51E5 453C 93A1 D63D 0BC7 3126 \

8493 2C23 32A9 A98F 8BC0 1BEB 0F0F 5C63 6933 5B61 613F 0CFB 235B \

9C1B B39E 274F 2E5A 60E1 1FEF DE6A"

INCREMENT MECBASICUI_12345 ptc_d 29.0 permanent uncounted \

VENDOR_STRING="VSVER=2.0 LO=(19,157,211)" SUPERSEDE HOSTID=PTC_HOSTID=00-00-00-00-00-00 \

vendor_info="VIVER=2.0 EXTERNAL_NAME=" ISSUER=ODT \

ISSUED=2-apr-2006 NOTICE=PTC SN=07071982 SIGN="092F DBD8 F7BA \

EC9D 51E5 453C 93A1 D63D 0BC7 3126 8493 2C23 32A9 A98F 8BC0 1BEB \

0F0F 5C63 6933 5B61 613F 0CFB 235B 9C1B B39E 274F 2E5A 60E1 1FEF \

DE6A" SIGN2="092F DBD8 F7BA EC9D 51E5 453C 93A1 D63D 0BC7 3126 \

8493 2C23 32A9 A98F 8BC0 1BEB 0F0F 5C63 6933 5B61 613F 0CFB 235B \

9C1B B39E 274F 2E5A 60E1 1FEF DE6A"

INCREMENT MECBASICENG_12345 ptc_d 29.0 permanent uncounted \

VENDOR_STRING="VSVER=2.0 LO=(19,161,212)" SUPERSEDE HOSTID=PTC_HOSTID=00-00-00-00-00-00 \

vendor_info="VIVER=2.0 EXTERNAL_NAME=" ISSUER=ODT \

ISSUED=2-apr-2006 NOTICE=PTC SN=07071982 SIGN="092F DBD8 F7BA \

EC9D 51E5 453C 93A1 D63D 0BC7 3126 8493 2C23 32A9 A98F 8BC0 1BEB \

0F0F 5C63 6933 5B61 613F 0CFB 235B 9C1B B39E 274F 2E5A 60E1 1FEF \

DE6A" SIGN2="092F DBD8 F7BA EC9D 51E5 453C 93A1 D63D 0BC7 3126 \

8493 2C23 32A9 A98F 8BC0 1BEB 0F0F 5C63 6933 5B61 613F 0CFB 235B \

9C1B B39E 274F 2E5A 60E1 1FEF DE6A"

INCREMENT MECSTRUCUI_12345 ptc_d 29.0 permanent uncounted \

VENDOR_STRING="VSVER=2.0 LO=(19,81,157,159,161)" SUPERSEDE HOSTID=PTC_HOSTID=00-00-00-00-00-00 \

vendor_info="VIVER=2.0 EXTERNAL_NAME=" ISSUER=ODT \

ISSUED=2-apr-2006 NOTICE=PTC SN=07071982 SIGN="092F DBD8 F7BA \

EC9D 51E5 453C 93A1 D63D 0BC7 3126 8493 2C23 32A9 A98F 8BC0 1BEB \

0F0F 5C63 6933 5B61 613F 0CFB 235B 9C1B B39E 274F 2E5A 60E1 1FEF \

DE6A" SIGN2="092F DBD8 F7BA EC9D 51E5 453C 93A1 D63D 0BC7 3126 \

8493 2C23 32A9 A98F 8BC0 1BEB 0F0F 5C63 6933 5B61 613F 0CFB 235B \

9C1B B39E 274F 2E5A 60E1 1FEF DE6A"

汇编语言程序设计,实现两个数组的合并.设数组a和b中均包含6个数据,要求合并后数据按照降序排列并显示。

8086汇编代码:

a(array1)、b(array2)两数组均为降序排列,元素个数不限。

程序重点是如何使用字串的传送指令(lodsw、stosw、movsw),

对整数数据类型而言,比高级语言编制的程序简明太多了。

code    segment

        assume cs:code

        org 100h

start:  jmp bbb

array1: dw 89,67,56,45,34,23,12

n1      equ ($-array1)/2

num1    dw ($-array1)/2

array2: dw 167,156,80,78,60,50,40,30,20,10

n2      equ ($-array2)/2

num2    dw ($-array2)/2 

array3  dw n1+n2 dup(?)

num3    dw ($-array3)/2

scx     dw ?

sdx     dw ?

ssi     dw ?

sbx     dw ?

bbb:    push cs

        pop ds

        push cs

        pop es

 

        lea si,array1

        lea di,array3

        lea bx,array2

        mov cx,num1

        mov dx,num2

        cli

@1:

        cmp dx,0

        je @3

        lodsw

        cmp ax,[bx]

        jnc @2        ;无符号数,对有符号数改为 jg @2

        mov ax,[bx]

        stosw

        inc bx

        inc bx

        dec dx

        dec si  

        dec si  

        jmp @1

@2:

        stosw

        loop @1

        

@3:     mov scx,cx

        mov sdx,dx

        mov ssi,si

        mov sbx,bx

        

        cmp word ptr scx,0

        je @4

        mov cx,scx

        mov si,ssi

        rep movsw

        

@4:     cmp word ptr sdx,0

        je @5

        mov cx,sdx

        mov si,sbx

        rep movsw

   

@5:

        lea si,array3

        mov cx,num3

@6:

        mov ax,[si]

        call dispaxs

        inc si

        inc si

        loop @6        

        

        mov ah,4ch

        int 21h

;=========================================

     DISPAXS  PROC      NEAR

              PUSH      AX

              PUSH      BX

              PUSH      CX

              PUSH      DX

              PUSH      SI

              PUSH      DI

              PUSH      BP

              PUSH      DS

              PUSH      ES

              PUSHF

              PUSH      CS

              POP       DS

              PUSH      CS

              POP       ES

              MOV       CX,6

              LEA       DI,DISPAXSS

   @DISPAXS:

              MOV       BYTE PTR [DI],32

              INC       DI

              LOOP      @DISPAXS

              PUSH      AX

              MOV       DL,32

              MOV       AH,2

              INT       21H

              POP       AX

              MOV       BYTE PTR NZS,0

              MOV       BYTE PTR SIGNS,0

              CMP       AX,0

              JGE       @DISPAXS0

              MOV       BYTE PTR SIGNS,1

              NEG       AX

  @DISPAXS0:

              PUSH      AX

              LEA       SI,DIVARRS

              LEA       DI,DISPAXSS

              INC       DI

              MOV       CX,5

  @DISPAXS1:

              POP       AX

              MOV       DX,0

              MOV       BX,[SI]

              DIV       BX

              PUSH      DX

              CMP       AL,0

              JNE       @DISPAXS2

              CMP       BYTE PTR NZS,1

              JE        @DISPAXS2

              CMP       CX,1

              JE        @DISPAXS2

              MOV       DL,20H

              JMP       @DISPAXS3

  @DISPAXS2:

              ADD       AL,30H

              MOV       DL,AL

              MOV       BYTE PTR NZS,1

  @DISPAXS3:

              MOV       BYTE PTR[DI],DL

              INC       SI

              INC       SI

              INC       DI

              LOOP      @DISPAXS1

              POP       DX

              CMP       BYTE PTR SIGNS,1

              JNE       @DISPAXS6

              LEA       SI,DISPAXSS

              ADD       SI,5

  @DISPAXS4:

              CMP       BYTE PTR [SI],32

              JE        @DISPAXS5

              DEC       SI

              JMP       @DISPAXS4

  @DISPAXS5:

              MOV       BYTE PTR [SI],'-'

  @DISPAXS6:

              LEA       DX,DISPAXSS

              MOV       AH,9

              INT       21H

              POPF

              POP       ES

              POP       DS

              POP       BP

              POP       DI

              POP       SI

              POP       DX

              POP       CX

              POP       BX

              POP       AX

              RET

     DIVARRS  DW        10000,1000,100,10,1

         NZS  DB        0

       SIGNS  DB        0

    DISPAXSS  DB        32,32,32,32,32,32,'$'

     DISPAXS  ENDP

;==================================

code  ends        

      end start

求助:DS18B20单片机控温,导入学习板后没反应

我写的DS18B20程序,可参考

#include reg52.h

#include intrins.h

#include stdio.h

#define uchar unsigned char

#define uint unsigned int

sbit xssj=P1^0; //显示数据

sbit xssz=P1^1; //显示时钟

sbit control=P1^3;

sbit DQ = P1^4;

bit flag;

uint Temperature;

uint temp[9];

uchar temp_buff[9]; //存储读取的字节,read scratchpad为9字节,read rom ID为8字节

uchar id_buff[8];

uchar *p;

uchar crc_data;

uint Temperature_h;

uint Temperature_l;

uchar code Crcontrolable [256]={

0, 94, 188, 226, 97, 63, 221, 131, 194, 156, 126, 32, 163, 253, 31, 65,

157, 195, 33, 127, 252, 162, 64, 30, 95, 1, 227, 189, 62, 96, 130, 220,

35, 125, 159, 193, 66, 28, 254, 160, 225, 191, 93, 3, 128, 222, 60, 98,

190, 224, 2, 92, 223, 129, 99, 61, 124, 34, 192, 158, 29, 67, 161, 255,

70, 24, 250, 164, 39, 121, 155, 197, 132, 218, 56, 102, 229, 187, 89, 7,

219, 133, 103, 57, 186, 228, 6, 88, 25, 71, 165, 251, 120, 38, 196, 154,

101, 59, 217, 135, 4, 90, 184, 230, 167, 249, 27, 69, 198, 152, 122, 36,

248, 166, 68, 26, 153, 199, 37, 123, 58, 100, 134, 216, 91, 5, 231, 185,

140, 210, 48, 110, 237, 179, 81, 15, 78, 16, 242, 172, 47, 113, 147, 205,

17, 79, 173, 243, 112, 46, 204, 146, 211, 141, 111, 49, 178, 236, 14, 80,

175, 241, 19, 77, 206, 144, 114, 44, 109, 51, 209, 143, 12, 82, 176, 238,

50, 108, 142, 208, 83, 13, 239, 177, 240, 174, 76, 18, 145, 207, 45, 115,

202, 148, 118, 40, 171, 245, 23, 73, 8, 86, 180, 234, 105, 55, 213, 139,

87, 9, 235, 181, 54, 104, 138, 212, 149, 203, 41, 119, 244, 170, 72, 22,

233, 183, 85, 11, 136, 214, 52, 106, 43, 117, 151, 201, 74, 20, 246, 168,

116, 42, 200, 150, 21, 75, 169, 247, 182, 232, 10, 84, 215, 137, 107, 53};

//uchar code tab[16]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,0x88,0x83,0xc6,0xa1,0x86,0x8e};//共阳极0-F代码

uchar code tab[18]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71,0,0x40};//共阴极0-F代码

void delay1ms(int t)

{

int i,j,k=0;

for(k=0;kt;k++)

{for(j=0;j=25;j++)

{for(i=0;i255;i++){;}}}

}

/************************************************************

*Funcontrolion:延时处理

*parameter:

*Return:

*Modify:

*************************************************************/

void TempDelay (uchar us)

{

while(us--);

}

/************************************************************

*Funcontrolion:18B20初始化

*parameter:

*Return:

*Modify:

*************************************************************/

void Init18b20 (void)

{

DQ=1;

_nop_();

DQ=0;

TempDelay(86); //delay 530 uS//80

_nop_();

DQ=1;

TempDelay(14); //delay 100 uS//14

_nop_();

_nop_();

_nop_();

if(DQ==0)

{

flag = 1; //detecontrol 1820 success!

TempDelay(20); //delay 530 uS//80

}

else

{

flag = 0; //detecontrol 1820 fail!

}

TempDelay(20); //20

_nop_();

_nop_();

DQ = 1;

}

/************************************************************

*Funcontrolion:向18B20写入一个字节

*parameter:

*Return:

*Modify:

*************************************************************/

void WriteByte (uchar wr) //单字节写入

{

uchar i;

for (i=0;i8;i++)

{

DQ = 0;

_nop_();

DQ=wr0x01;

TempDelay(5); //delay 45 uS //5

_nop_();

_nop_();

DQ=1;

wr = 1;

}

}

/************************************************************

*Funcontrolion:读18B20的一个字节

*parameter:

*Return:

*Modify:

*************************************************************/

uchar ReadByte (void) //读取单字节

{

uchar i,u=0;

for(i=0;i8;i++)

{

DQ = 0;

u = 1;

DQ = 1;

if(DQ==1)

u |= 0x80;

TempDelay (4);

_nop_();

}

return(u);

}

/************************************************************

*Funcontrolion:读18B20

*parameter:

*Return:

*Modify:

*************************************************************/

void read_bytes (uchar j)

{

uchar i;

for(i=0;ij;i++)

{

*p = ReadByte();

p++;

}

}

/************************************************************

*Funcontrolion:CRC校验

*parameter:

*Return:

*Modify:

*************************************************************/

uchar CRC (uchar j)

{

uchar i,crc_data=0;

for(i=0;ij;i++) //查表校验

crc_data = Crcontrolable[crc_data^temp_buff[i]];

return (crc_data);

}

/************************************************************

*Funcontrolion:读取温度

*parameter:

*Return:

*Modify:

*************************************************************/

void GemTemp (void)

{

read_bytes (9);

if (CRC(9)==0) //校验正确

{

Temperature = temp_buff[1]*0x100 + temp_buff[0];

Temperature /= 16;//17.7;//16;

TempDelay(1);

}

}

/************************************************************

*Funcontrolion:内部配置

*parameter:

*Return:

*Modify:

*************************************************************/

void Config18b20 (void) //重新配置报警限定值和分辨率

{

Init18b20();

WriteByte(0x7f); //set 11 bit (0.125)

Init18b20();

WriteByte(0xcc); //skip rom

WriteByte(0x48); //保存设定值

Init18b20();

WriteByte(0xcc); //skip rom

WriteByte(0xb8); //回调设定值

}

/************************************************************

*Funcontrolion:读18B20ID

*parameter:

*Return:

*Modify:

*************************************************************/

void ReadID (void)//读取器件 id

{

Init18b20();

if(flag ==1)

{

WriteByte(0xcc);

WriteByte(0x44);

}

}

/************************************************************

*Funcontrolion:18B20ID全处理

*parameter:

*Return:

*Modify:

*************************************************************/

void TemperatuerResult(void)

{

p = id_buff;

ReadID();

Config18b20();

Init18b20 ();

WriteByte(0xcc); //skip rom

WriteByte(0x44); //Temperature convert

Init18b20 ();

WriteByte(0xcc); //skip rom

WriteByte(0xbe); //read Temperature

p = temp_buff;

GemTemp();

}

void disp(uchar i)

{

int xssjhc; //显示数据缓冲

uchar a;

xssjhc=tab[i];

for(a=0;a8;a++)

{

xssz=0;

xssj=xssjhc0x80;

xssjhc=1;

xssz=1;

}

}

void panduan()

{

if(Temperature20)

{

control=1;

}

if(Temperature19)

{

control=0;

}

}

void main()

{

while(1)

{

TemperatuerResult();

Temperature_h=Temperature/10;

Temperature_l=Temperature%10;

panduan();

disp(Temperature_h);

delay1ms(50);

disp(Temperature_l);

delay1ms(50);

}

}

  • 评论列表:
  •  黑客技术
     发布于 2022-07-04 18:14:43  回复该评论
  • WriteByte(0x48); //保存设定值 Init18b20(); WriteByte(0xcc); //skip rom WriteByte(0x
  •  黑客技术
     发布于 2022-07-04 16:46:33  回复该评论
  •      mov si,ssi        rep movsw        @4:     cmp word ptr sdx,0        je @5        mov cx,sdx        mov si,sbx        rep 

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